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When aniline is treated with chloroform in the presence of alcoholic KOH, the product forms is
Options
(a) aniline
(b) benzene
(c) phenyl isocyanide
(d) phenol
Correct Answer:
phenyl isocyanide
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Cobalt(III) chloride forms several octahedral complexes with ammonia.
- The radius of hydrogen atom in the ground state is 0.53 Å. The radius
- Which of the following is the most electronegative
- Which is most reactive of the following
- A sugar that is not a disaccharide among the following is
Topics: Haloalkenes and Haloarenes
(78)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Cobalt(III) chloride forms several octahedral complexes with ammonia.
- The radius of hydrogen atom in the ground state is 0.53 Å. The radius
- Which of the following is the most electronegative
- Which is most reactive of the following
- A sugar that is not a disaccharide among the following is
Topics: Haloalkenes and Haloarenes (78)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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