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When aniline is treated with chloroform in the presence of alcoholic KOH, the product forms is
Options
(a) aniline
(b) benzene
(c) phenyl isocyanide
(d) phenol
Correct Answer:
phenyl isocyanide
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Ionisation constant of CH₃COOH is 1.7 ˣ 10⁻⁵ and concentration of H⁺ ions
- Two chemicals having same chemical formula but different arrangement of atoms
- Which one of the following esters gets hydrolysde most easily under alkaline
- Which metal is extracted by complexing with KCN
- Electronic configuration of deuterium atom is
Topics: Haloalkenes and Haloarenes
(78)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Ionisation constant of CH₃COOH is 1.7 ˣ 10⁻⁵ and concentration of H⁺ ions
- Two chemicals having same chemical formula but different arrangement of atoms
- Which one of the following esters gets hydrolysde most easily under alkaline
- Which metal is extracted by complexing with KCN
- Electronic configuration of deuterium atom is
Topics: Haloalkenes and Haloarenes (78)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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