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When aniline is treated with chloroform in the presence of alcoholic KOH, the product forms is
Options
(a) aniline
(b) benzene
(c) phenyl isocyanide
(d) phenol
Correct Answer:
phenyl isocyanide
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Haloalkenes and Haloarenes
(78)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Sodium thiosulphate is added in photography to
- The ratio of the difference in energy between first and second Bohr orbit
- Rectified spirit has ethanol
- What is the maximum number of electrons that can be associated with the following
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Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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