| ⇦ | 
| ⇨ |
When acetone reacts with bleaching powder, the compound formed is
Options
(a) CCl₄
(b) CHCl₃
(c) CH₃CHO
(d) CH₃COOH
Correct Answer:
CHCl₃
Explanation:
It involves two steps: CaOCl₂(Bleaching powder) + H₂O → Ca(OH)₂ + Cl₂ . (i)Chlorination of acetone to form trichloroacetone. CH₃COCH₃ + 3Cl₂ → CCl₃COCH₃ + 3HCl. (ii) Trichloroacetone is hydrolysed by Ca(OH)₂ present in bleaching powder to give chloroform. 2CCl₃COCH₃ + Ca(OH)₂ → 2CHCl₃(Chloroform) + (CH₃COO)₂Ca(Calcium acetate).
Related Questions: - Empirical formula of a compound is CH₂O.If its molecular weight is 180,
- A 0.66 kg ball is moving with a speed of 100 m/s. The associated wavelength
- Ethyne can be oxidised to oxalic acid by using
- The oxidation number of oxygen in O₂PtF₆ is
- The reduction of benzoyl chloride with H₂/Pd BaSO₄ gives
Topics: Haloalkenes and Haloarenes
(78)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Empirical formula of a compound is CH₂O.If its molecular weight is 180,
- A 0.66 kg ball is moving with a speed of 100 m/s. The associated wavelength
- Ethyne can be oxidised to oxalic acid by using
- The oxidation number of oxygen in O₂PtF₆ is
- The reduction of benzoyl chloride with H₂/Pd BaSO₄ gives
Topics: Haloalkenes and Haloarenes (78)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply