When a string is divided into three segments of length l₁, l₂ and l₃ the fundamental

When A String Is Divided Into Three Segments Of Length Physics Question

When a string is divided into three segments of length l₁, l₂ and l₃ the fundamental frequencies of these three segments are v₁, v₂ and v₃ respectively. The original fundamental frequency (v) of the string is

Options

(a) √v = √v₁ + √v₂ + √v₃
(b) v = v₁ + v₂ + v₃
(c) 1/v = 1/v₁ + 1/v₂ + 1/v₃
(d) 1/ √v = 1/ √v₁ + 1/ √v₂ + 1/ √v₃

Correct Answer:

1/v = 1/v₁ + 1/v₂ + 1/v₃

Explanation:

Fundamental frequency is given by v = 1/ 2l √(T / µ)
⇒ v ∞ 1/ l ⇒ P ∞ 1 / v Since, P divided into l₁, l₂ and l₃ segments.
Here, l = l₁ + l₂ + l₃
So, 1/v = 1/v₁ + 1/v₂ + 1/v₃

Related Questions:

  1. A heavy nucleus at rest breaks into two fragments which fly off with velocities
  2. A stone is tied to a string of length l and whirled in a vertical circle with the other end
  3. The magnetic susceptibility of a material of a rod is 299. Permeability of vacuum
  4. Two bubbles A and B (A>B) are joined through a narrow tube. Then
  5. A ship A is moving westwards with a speed of 10 km/h and a ship B 100 km

Topics: Waves (80)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*