⇦ | ![]() | ⇨ |
When a string is divided into three segments of length l₁, l₂ and l₃ the fundamental frequencies of these three segments are v₁, v₂ and v₃ respectively. The original fundamental frequency (v) of the string is
Options
(a) √v = √v₁ + √v₂ + √v₃
(b) v = v₁ + v₂ + v₃
(c) 1/v = 1/v₁ + 1/v₂ + 1/v₃
(d) 1/ √v = 1/ √v₁ + 1/ √v₂ + 1/ √v₃
Correct Answer:
1/v = 1/v₁ + 1/v₂ + 1/v₃
Explanation:
Fundamental frequency is given by v = 1/ 2l √(T / µ)
⇒ v ∞ 1/ l ⇒ P ∞ 1 / v Since, P divided into l₁, l₂ and l₃ segments.
Here, l = l₁ + l₂ + l₃
So, 1/v = 1/v₁ + 1/v₂ + 1/v₃
Related Questions:
- Electrons in the atom are held to the nucleus by
- Two radioactive materials X₁ and X₂ have decay constants 5λ and λ respectively
- Two capacitors 3μF and 4μF, are individually charged across a 6 V battery.
- Sodium has body centred packing. Distance between two nearest atoms is 3.7 Å.
- According to Bohr model of hydrogen atom, only those orbits are permissible
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply