⇦ | ![]() | ⇨ |
When a Daniel cell is connected in the secondary circuit of a potentiometer, the balancing length is found to be 540 cm. If the balancing length becomes 500 cm when the cell is short circuited with 1 Ω, the internal resistance of the cell is
Options
(a) 0.08 Ω
(b) 0.04 Ω
(c) 1.45 Ω
(d) 1.08 Ω
Correct Answer:
0.08 Ω
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions:
- A pure semiconductor behaves slightly as a conductor at
- A missile is fired for maximum range with an initial velocity of 20 m/s
- If the number of radius of ²⁷Al is 3.6 Fermi, the approximate nuclear radius
- A body is moving with velocity 30 m/s towards east. After 10 seconds its velocity
- The temperature coefficient of a resistance wire is 0.00125 per degree.
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
((Final length-initial length)/initial length )×resistence increased
((540-500)/500 )×1=40/500=0.08ohm