| ⇦ |
| ⇨ |
When a Daniel cell is connected in the secondary circuit of a potentiometer, the balancing length is found to be 540 cm. If the balancing length becomes 500 cm when the cell is short circuited with 1 Ω, the internal resistance of the cell is
Options
(a) 0.08 Ω
(b) 0.04 Ω
(c) 1.45 Ω
(d) 1.08 Ω
Correct Answer:
0.08 Ω
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A particle having a mass of 10⁻² kg carries a charge of 5 x 10⁻⁸C
- An ideal gas is compressed to half its initial volume by means of several processes.
- When two identical capacitors are in series, they have 3 μF capacitance
- A resistor 30Ω, inductor of reactance 10 Ω and capacitor of reactance 10 Ω
- If the velocity of an electron increases, then its de Broglie wavelength will
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle having a mass of 10⁻² kg carries a charge of 5 x 10⁻⁸C
- An ideal gas is compressed to half its initial volume by means of several processes.
- When two identical capacitors are in series, they have 3 μF capacitance
- A resistor 30Ω, inductor of reactance 10 Ω and capacitor of reactance 10 Ω
- If the velocity of an electron increases, then its de Broglie wavelength will
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

((Final length-initial length)/initial length )×resistence increased
((540-500)/500 )×1=40/500=0.08ohm