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When a current of (2.5±0.5) A flows through a wire, it develops a potential difference of (20±1) V, then the resistance of wire is
Options
(a) (8±2)Ω
(b) (8±1.6)Ω
(c) (8±1.5)Ω
(d) (8±3)Ω
Correct Answer:
(8±2)Ω
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Subject: Physics
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- The equiconvex lens has focal length f. If it is cut perpendicular to the principal
- Two positive ions, each carrying a charge q, are separated by a distance d
- Light of wavelength 500 nm is incident on a metal with work function 2.28 eV.
- A particle of mass m is projected with a velocity v making an angle of 45°
- A particle moves along the x-axis from x=0 to x=5 m under the influence of a force
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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R=V/I
R=20/2.5
R= 8 ohm
Now,
∆ R/R=∆ V/V+∆I/I
=1/20 +0.5/2.5
= 1/4
Therefore,
∆ R÷R=1÷4
∆ R=1÷4×R
∆R=1÷4×8
∆R=2
Therefore,
Resistance with error limits=R+ – ∆R
=(8+ – 2)ohm