When 22.4 litres of H₂(g) is mixed with 11.2 litres of Cl₂(g) each at S.T.P,

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When 22.4 litres of H₂(g) is mixed with 11.2 litres of Cl₂(g) each at S.T.P, the moles of HCl(g) formed is equal to

Options

(a) 1 mol of HCl(g)
(b) 2 mol of HCl(g)
(c) 0.5 mol of HCl(g)
(d) 1.5 mol of HCl(g)

Correct Answer:

1 mol of HCl(g)

Explanation:

H₂ +Cl₂ → 2HCl
t=0 ,22.4,11.2 lit , 0
t=0,or 1 mole, 0.5 mole, 0
at time t (1-0.5) =0.5
0.5×2 = 1 mole

Related Questions:

1. The first ionisation potential will be maximum for
2. Which of the following is the smallest anion
3. Packing efficiency of hcp structure is
4. Which does not exist
5. Which of the following pairs of a chemical reaction is certain to result

Topics: Some Basic concepts of Chemistry (5)
Subject: Chemistry (2512)

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