| ⇦ | 
| ⇨ |
When 22.4 litres of H₂(g) is mixed with 11.2 litres of Cl₂(g) each at S.T.P, the moles of HCl(g) formed is equal to
Options
(a) 1 mol of HCl(g)
(b) 2 mol of HCl(g)
(c) 0.5 mol of HCl(g)
(d) 1.5 mol of HCl(g)
Correct Answer:
1 mol of HCl(g)
Explanation:
H₂ +Cl₂ → 2HCl
t=0 ,22.4,11.2 lit , 0
t=0,or 1 mole, 0.5 mole, 0
at time t (1-0.5) =0.5
0.5×2 = 1 mole
Related Questions: - An increase in equivalent conductance of a strong electrolyte
- Which one of the following pairs represents stereoisomerism
- When ethanal is treated with Fehling’s solution. it gives a precipitate of
- What is the pH of the resulting solution when equal volumes of 0.1 M NaOH
- In NH₃ and PH₃, the common feature is
Topics: Some Basic concepts of Chemistry
(5)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An increase in equivalent conductance of a strong electrolyte
- Which one of the following pairs represents stereoisomerism
- When ethanal is treated with Fehling’s solution. it gives a precipitate of
- What is the pH of the resulting solution when equal volumes of 0.1 M NaOH
- In NH₃ and PH₃, the common feature is
Topics: Some Basic concepts of Chemistry (5)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply