| ⇦ | 
| ⇨ |
When 1 kg of ice at 0⁰C melts to water at 0⁰C, the resulting change in its entropy, taking latent heat of ice to be 80 cal/⁰C, is
Options
(a) 273 cal/K
(b) 8 x 104 cal/K
(c) 80 cal/K
(d) 293 cal/K
Correct Answer:
293 cal/K
Explanation:
Change in entropy is given by
dS = dQ / T or ∆S = ∆Q / T = mLf / 273
∆S = 1000 x 80 / 273 = 293cal / K
Related Questions: - Dimensions of resistance in an electrical circuit, in terms of dimension of mass M,
- A beaker of radius 1.5 cm is filled with a liquid of surface tension 0.075 N/m
- What is the dimension of impedance?
- λ₁ and λ₂ are used to illuminate the slits. β₁ and β₂ are the corresponding fringe
- A string in musical instrument is 50 cm long and its fundamental frequency is 800 Hz.
Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Dimensions of resistance in an electrical circuit, in terms of dimension of mass M,
- A beaker of radius 1.5 cm is filled with a liquid of surface tension 0.075 N/m
- What is the dimension of impedance?
- λ₁ and λ₂ are used to illuminate the slits. β₁ and β₂ are the corresponding fringe
- A string in musical instrument is 50 cm long and its fundamental frequency is 800 Hz.
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply