| ⇦ |
| ⇨ |
When 1 kg of ice at 0⁰C melts to water at 0⁰C, the resulting change in its entropy, taking latent heat of ice to be 80 cal/⁰C, is
Options
(a) 273 cal/K
(b) 8 x 104 cal/K
(c) 80 cal/K
(d) 293 cal/K
Correct Answer:
293 cal/K
Explanation:
Change in entropy is given by
dS = dQ / T or ∆S = ∆Q / T = mLf / 273
∆S = 1000 x 80 / 273 = 293cal / K
Related Questions: - An electric dipole of dipole moment p is aligned parallel to a uniform electric field E
- To observed diffraction, the size of the obstacle
- A wheel has angular acceleration of 3.0 rad/sec² and an initial angular speed
- The de-Broglie wavelength of an electron moving with a velocity 1.5×10⁸ ms⁻¹ is equal
- An unpolarised beam of intensity I₀ falls on a polaroid. The intensity
Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An electric dipole of dipole moment p is aligned parallel to a uniform electric field E
- To observed diffraction, the size of the obstacle
- A wheel has angular acceleration of 3.0 rad/sec² and an initial angular speed
- The de-Broglie wavelength of an electron moving with a velocity 1.5×10⁸ ms⁻¹ is equal
- An unpolarised beam of intensity I₀ falls on a polaroid. The intensity
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply