| ⇦ | 
| ⇨ |
When 1 kg of ice at 0⁰C melts to water at 0⁰C, the resulting change in its entropy, taking latent heat of ice to be 80 cal/⁰C, is
Options
(a) 273 cal/K
(b) 8 x 104 cal/K
(c) 80 cal/K
(d) 293 cal/K
Correct Answer:
293 cal/K
Explanation:
Change in entropy is given by
dS = dQ / T or ∆S = ∆Q / T = mLf / 273
∆S = 1000 x 80 / 273 = 293cal / K
Related Questions: - How much work is required to carry a 6 μC charge from the negative terminal
- Imagine a new planet having the same density as that of earth but it is 3 times bigger
- A resistance of 20 ohm is connected to a source of an alternating potential V
- In Young’s double slit experiment, the locus of the point P lying in a plane
- A body of weight W newton is at the surface of the earth.
Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- How much work is required to carry a 6 μC charge from the negative terminal
- Imagine a new planet having the same density as that of earth but it is 3 times bigger
- A resistance of 20 ohm is connected to a source of an alternating potential V
- In Young’s double slit experiment, the locus of the point P lying in a plane
- A body of weight W newton is at the surface of the earth.
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply