| ⇦ | 
| ⇨ |
When ₉₀Th²²⁸ transforms to ₈₃Bi²¹², the number of emitted α and β particles are respectively
Options
(a) 8 α,7 β
(b) 4 α,7 β
(c) 4 α,4 β
(d) 4 α,1 β
Correct Answer:
4 α,1 β
Explanation:
α-particle = ₂He⁴, β-particle = ₋₁β and Nucleus = zXᴬ
Change in A occurs only due to α-emission.
Change in A = 228 – 212 = 16
This change is due to 4 α.
Again change in Z = 90 – 83 = 7
Change in Z due to 4α = 8
.·. Change in Z due to β = 8 – 7 = 1
This is due to one β.
Hence particles emitted = 4α, 1β.
Related Questions: - In the half wave rectifier circuit operating from 50 Hz mains frequency,
- In an electrical circuit R,L,C and an AC voltage source are all connected in series.
- A bubble is rising from bottom of a lake. The volume of bubble becomes
- The acceleration of an electron in an electric field of magnitude 50 V/cm,
- A force acts on a 3.0 g particle in such a way that the position of the particle
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In the half wave rectifier circuit operating from 50 Hz mains frequency,
- In an electrical circuit R,L,C and an AC voltage source are all connected in series.
- A bubble is rising from bottom of a lake. The volume of bubble becomes
- The acceleration of an electron in an electric field of magnitude 50 V/cm,
- A force acts on a 3.0 g particle in such a way that the position of the particle
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply