When ₉₀Th²²⁸ transforms to ₈₃Bi²¹², the number of emitted α and β particles

⇦

⇨

When ₉₀Th²²⁸ transforms to ₈₃Bi²¹², the number of emitted α and β particles are respectively

Options

(a) 8 α,7 β
(b) 4 α,7 β
(c) 4 α,4 β
(d) 4 α,1 β

Correct Answer:

4 α,1 β

Explanation:

α-particle = ₂He⁴, β-particle = ₋₁β and Nucleus = zXᴬ

Change in A occurs only due to α-emission.

Change in A = 228 – 212 = 16

This change is due to 4 α.

Again change in Z = 90 – 83 = 7

Change in Z due to 4α = 8

.·. Change in Z due to β = 8 – 7 = 1

This is due to one β.

Hence particles emitted = 4α, 1β.

Related Questions:

1. The kinetic energy needed to project a body of mass m from the surface of earth
2. During production of cathode ray
3. The order of distance of an electron revolving in an atom from nucleus is
4. A body weighs 50 grams in air and 40 grams in water. How much would it weigh in a liquid
5. Assertion(A) :The change in kinetic energy of a particle is equal to the work done

Topics: Radioactivity (83)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends