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When ₉₀Th²²⁸ transforms to ₈₃Bi²¹², the number of emitted α and β particles are respectively
Options
(a) 8 α,7 β
(b) 4 α,7 β
(c) 4 α,4 β
(d) 4 α,1 β
Correct Answer:
4 α,1 β
Explanation:
α-particle = ₂He⁴, β-particle = ₋₁β and Nucleus = zXᴬ
Change in A occurs only due to α-emission.
Change in A = 228 – 212 = 16
This change is due to 4 α.
Again change in Z = 90 – 83 = 7
Change in Z due to 4α = 8
.·. Change in Z due to β = 8 – 7 = 1
This is due to one β.
Hence particles emitted = 4α, 1β.
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body covers 200 cm in the first 2 seconds and 220 cm in the next 4 seconds.
- A particle of mass 1.96×10⁻¹⁵ kg is kept in equilibrium between two horizontal metal
- The upper half of an inclined plane of inclination θ is perfectly smooth while lower
- Two simple harmonic motions of angular frequency 100 and 1000 rad s⁻¹ have the same
- The relationship between decay constant λ and half-life T of a radioactive substance is
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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