When ₉₀Th²²⁸ transforms to ₈₃Bi²¹², the number of emitted α and β particles

⇦

⇨

When ₉₀Th²²⁸ transforms to ₈₃Bi²¹², the number of emitted α and β particles are respectively

Options

(a) 8 α,7 β
(b) 4 α,7 β
(c) 4 α,4 β
(d) 4 α,1 β

Correct Answer:

4 α,1 β

Explanation:

α-particle = ₂He⁴, β-particle = ₋₁β and Nucleus = zXᴬ

Change in A occurs only due to α-emission.

Change in A = 228 – 212 = 16

This change is due to 4 α.

Again change in Z = 90 – 83 = 7

Change in Z due to 4α = 8

.·. Change in Z due to β = 8 – 7 = 1

This is due to one β.

Hence particles emitted = 4α, 1β.

Related Questions:

1. A circular disc rolls down an inclined plane.The ratio of rotational kinetic energy
2. A balloon with mass m is descending down with an acceleration a
3. In a Rutherford scattering experiment when a projectile of charge Z₁ and mass M₁
4. An oscillator circuit consists of an inductance of 0. mH and a capacitor of 20 μF.
5. Wavefront is the locus of all points, where the particles of the medium

Topics: Radioactivity (83)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends