| ⇦ | 
| ⇨ |
What will be the direction of movement of water, when a solution A having water potential of – 9 bars and another solution of B of -4 bars is separated by a semipermeable membrane?
Options
(a) B to A
(b) In both A and B directions
(c) A to B
(d) only B directions
Correct Answer:
B to A
Explanation:
The direction of water movement is always from higher wate potential to lower water potential i.e. in energetically downhill direction, the direction of water in this case will be from -4 bars to -9 bars or from solution B to solution A through the semipermeable membrane.
Related Questions: - Guttation occurs in
- A population will not exist in Hardy -Weinberg equilibrium if :
- Which of the following is a pair of motor nerves?
- Typical growth curve in plants is :
- The condition trisomic is referred to as
Topics: Transport and Nutrition in Plants
(163)
Subject: Biology
(4253)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Guttation occurs in
- A population will not exist in Hardy -Weinberg equilibrium if :
- Which of the following is a pair of motor nerves?
- Typical growth curve in plants is :
- The condition trisomic is referred to as
Topics: Transport and Nutrition in Plants (163)
Subject: Biology (4253)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply