| ⇦ | 
| ⇨ |
What is the voltage gain in a common-emiiter amplifier, when input resistance is 4 Ω and load resistance is 24 Ω? Take β=0.6
Options
(a) 3.6
(b) 4.8
(c) 2.4
(d) 1.2
Correct Answer:
3.6
Explanation:
Input resistance Rᵢ = 4Ω
Load resistance Rʟ = 24Ω
Resistance gain = Rʟ / Rᵢ = 24Ω / 4Ω = 6
Current gain β = 0.6
Voltage gain = Current gain x Resistance gain
= 0.6 x 6 = 3.6
Related Questions: - Huygen’s principle of secondary wavelets may be used to
- If the magnetising field on a ferromagnetic material is increased, its permeability
- A thin and circular disc of mass M and radius R is rotating in a horizontal plane
- Light emitted during the de excitation of electron from n=3 to n=2, when incident
- The speed of light in media M₁ and M₂ are 1.5×10⁸ ms⁻¹ and 2×10⁸ ms⁻¹ respectively.
Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Huygen’s principle of secondary wavelets may be used to
- If the magnetising field on a ferromagnetic material is increased, its permeability
- A thin and circular disc of mass M and radius R is rotating in a horizontal plane
- Light emitted during the de excitation of electron from n=3 to n=2, when incident
- The speed of light in media M₁ and M₂ are 1.5×10⁸ ms⁻¹ and 2×10⁸ ms⁻¹ respectively.
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply