| ⇦ |
| ⇨ |
What is the pH of 0.01 M glycine solution? For glycine, Ka₁ = 4.5 ˣ 10⁻³ and Ka₂ =1.7 ˣ 10⁻¹⁰ at 298 K
Options
(a) 3
(b) 10
(c) 6.1
(d) 7.2
Correct Answer:
6.1
Explanation:
K = Kₐ₁ x Kₐ₂ = 4.5 x 10⁻³ * 1.7 x 10⁻¹⁰,
7.65 x 10⁻¹³,
[H⁺] = √KC = √7.65 x 10⁻¹³ x 0.01 ,
= √7.65 x 10⁻¹⁵
= 0.87 x 10⁻⁷. pH = -log 0.87 x 10⁻⁷
= 7 – 0.93 = 6.07.
Related Questions: - The correct bond order in the following species is
- Which of the following corresponds to the electronic configuration 1s², 2s²,2p⁶
- The standard heat of formation of carbon disulphide (l) given that the standard
- The number of valence electrons in 4.2g of N³⁻ ion is
- The complex [CoF₆]⁴⁻ is
Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The correct bond order in the following species is
- Which of the following corresponds to the electronic configuration 1s², 2s²,2p⁶
- The standard heat of formation of carbon disulphide (l) given that the standard
- The number of valence electrons in 4.2g of N³⁻ ion is
- The complex [CoF₆]⁴⁻ is
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply