⇦ | ![]() | ⇨ |
What is the pH of 0.01 M glycine solution? For glycine, Ka₁ = 4.5 ˣ 10⁻³ and Ka₂ =1.7 ˣ 10⁻¹⁰ at 298 K
Options
(a) 3
(b) 10
(c) 6.1
(d) 7.2
Correct Answer:
6.1
Explanation:
K = Kₐ₁ x Kₐ₂ = 4.5 x 10⁻³ * 1.7 x 10⁻¹⁰,
7.65 x 10⁻¹³,
[H⁺] = √KC = √7.65 x 10⁻¹³ x 0.01 ,
= √7.65 x 10⁻¹⁵
= 0.87 x 10⁻⁷. pH = -log 0.87 x 10⁻⁷
= 7 – 0.93 = 6.07.
Related Questions:
- How will you separate a solution (miscible) of benzene + CHCl₃
- Least voltage hydrogen halide is
- The ligand N(CH₂CH₂NH₂)₃ is
- In the Dumas method of estimation of nitrogen,the nitrogen in the organic compound
- Cynanide and reacts isocyanide are isomers of type
Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply