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What is the pH of 0.01 M glycine solution? For glycine, Ka₁ = 4.5 ˣ 10⁻³ and Ka₂ =1.7 ˣ 10⁻¹⁰ at 298 K
Options
(a) 3
(b) 10
(c) 6.1
(d) 7.2
Correct Answer:
6.1
Explanation:
K = Kₐ₁ x Kₐ₂ = 4.5 x 10⁻³ * 1.7 x 10⁻¹⁰,
7.65 x 10⁻¹³,
[H⁺] = √KC = √7.65 x 10⁻¹³ x 0.01 ,
= √7.65 x 10⁻¹⁵
= 0.87 x 10⁻⁷. pH = -log 0.87 x 10⁻⁷
= 7 – 0.93 = 6.07.
Related Questions: - In a period, the elements are arranged in strict sequence of
- The neutralisation of a strong acid by a strong base liberates an amount
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Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a period, the elements are arranged in strict sequence of
- The neutralisation of a strong acid by a strong base liberates an amount
- The hybridisation of carbons of C-C single bond of HC ≡C-CH =CH₂ is
- The following quantum numbers are possible for how many orbital(s)
- Which of the following statements is false
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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