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What is the oxidation number of Co in [Co(NH₃)₄Cl(NO₂)]
Options
(a) 4
(b) 3
(c) 2
(d) 5
Correct Answer:
2
Explanation:
[Co(NH₃)₄Cl(NO₂)] → x + 4 * 0 + (-1) + (-1) = 0 ⇒ x = +2. The oxidation number of cobalt in this complex is +2.
Related Questions: - The oxidation states of sulphur in the anions : SO₃²⁻,S₂O₄²⁻ and S₂O₆²⁻
- If an amide is treated with P₂O₅ the likely product is an
- Which is insoluble in water
- Square planar complex of the type MABXL(where A,B,X and L are unidentates) show
- The compound that does not produce blue colour in Lassaigne’s test is
Topics: Coordination Compounds
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The oxidation states of sulphur in the anions : SO₃²⁻,S₂O₄²⁻ and S₂O₆²⁻
- If an amide is treated with P₂O₅ the likely product is an
- Which is insoluble in water
- Square planar complex of the type MABXL(where A,B,X and L are unidentates) show
- The compound that does not produce blue colour in Lassaigne’s test is
Topics: Coordination Compounds (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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