What is the [OH⁻] in the final solution prepared by mixing 20 mL of 0.05 M Hcl

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What is the [OH⁻] in the final solution prepared by mixing 20 mL of 0.05 M Hcl with 30 mL of 0.1 M Ba(OH)₂?

Options

(a) 0.4 M
(b) 0.005 M
(c) 0.12 M
(d) 0.1 M

Correct Answer:

0.1 M

Explanation:

No of milliequivalent of HCl = 20 x 0.05 =1.0
No of milliequivalent of Br(OH)₂ = 30 x 0.1 x 2 = 60
after neutralization, no of milliequivalents in 50 ml of solution = 6-1=5
Total vol of solution = 20 + 30 = 50 ml
No of milliequivalent of OH⁻ is 5 in 50 ml
[OH⁻] = (5 x 100 / 10 ) x 10⁻³ = 0.1 M

Related Questions:

1. The strongest reducing agent among the following is
2. Which of the following hydrogen bonds are strongest in vapour phase
3. Which of the following species contains three bond pairs and one lone pair
4. The compound containing coordinate bond is
5. General electronic configuration of lanthanides is

Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)

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