What is the [OH⁻] in the final solution prepared by mixing 20 mL of 0.05 M Hcl

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What is the [OH⁻] in the final solution prepared by mixing 20 mL of 0.05 M Hcl with 30 mL of 0.1 M Ba(OH)₂?

Options

(a) 0.4 M
(b) 0.005 M
(c) 0.12 M
(d) 0.1 M

Correct Answer:

0.1 M

Explanation:

No of milliequivalent of HCl = 20 x 0.05 =1.0
No of milliequivalent of Br(OH)₂ = 30 x 0.1 x 2 = 60
after neutralization, no of milliequivalents in 50 ml of solution = 6-1=5
Total vol of solution = 20 + 30 = 50 ml
No of milliequivalent of OH⁻ is 5 in 50 ml
[OH⁻] = (5 x 100 / 10 ) x 10⁻³ = 0.1 M

Related Questions:

1. In which of the following pairs, both the species are not isostructural ?
2. The amount of energy,which is released due to the addition of extra electron
3. Unit of entropy is
4. preservative among the following is
5. In which of the following pairs of molecules/ions, the central atoms have

Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)

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