⇦ | ⇨ |
What is the magnetic moment for Mn²⁺ ion in low spin state
Options
(a) 5.90 BM
(b) 8.90 BM
(c) 2.8 BM
(d) 1.73 BM
Correct Answer:
1.73 BM
Explanation:
For Mn²⁺ ion in low spin state, number of unpaired electrons = 1. Magnetic moment = √n(n+2) =√1*3=1.73 BM.
Related Questions: - What is the maximum number of electrons that can be associated with the following
- In SN2 reaction the sequence of bond breaking and bond formation is as follows
- Among the following pairs of ions, the lower oxidation state in aqueous solution
- Glycerol on treated with oxalic acid gives
- An emulsion is a colloidal dispersion of
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- What is the maximum number of electrons that can be associated with the following
- In SN2 reaction the sequence of bond breaking and bond formation is as follows
- Among the following pairs of ions, the lower oxidation state in aqueous solution
- Glycerol on treated with oxalic acid gives
- An emulsion is a colloidal dispersion of
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply