| ⇦ | 
| ⇨ |
What is the magnetic moment for Mn²⁺ ion in low spin state
Options
(a) 5.90 BM
(b) 8.90 BM
(c) 2.8 BM
(d) 1.73 BM
Correct Answer:
1.73 BM
Explanation:
For Mn²⁺ ion in low spin state, number of unpaired electrons = 1. Magnetic moment = √n(n+2) =√1*3=1.73 BM.
Related Questions: - An orange dye, p-hydroxyazobenzene can be synthesized from benzene diazonium
- In the reaction : 4Fe + 3O₂ ⇌ 4Fe³⁺ + 6O₂²⁻. Which of the following
- Increasing order of rms velocities of H₂,O₂,N₂ and HBr is
- Ziegler Natta catalyst is an organometallic compound containing
- The fcc crystal contains how many atoms in each unit cell
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An orange dye, p-hydroxyazobenzene can be synthesized from benzene diazonium
- In the reaction : 4Fe + 3O₂ ⇌ 4Fe³⁺ + 6O₂²⁻. Which of the following
- Increasing order of rms velocities of H₂,O₂,N₂ and HBr is
- Ziegler Natta catalyst is an organometallic compound containing
- The fcc crystal contains how many atoms in each unit cell
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply