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What is the magnetic moment for Mn²⁺ ion in low spin state
Options
(a) 5.90 BM
(b) 8.90 BM
(c) 2.8 BM
(d) 1.73 BM
Correct Answer:
1.73 BM
Explanation:
For Mn²⁺ ion in low spin state, number of unpaired electrons = 1. Magnetic moment = √n(n+2) =√1*3=1.73 BM.
Related Questions: - In which of the following conditions a chemical reaction can not occur
- In liquid-gas equilibrium,the pressure of vapours above the liquid is constant
- Which of the following does not show electrical conduction
- Number of moles of MnO₄⁻ required to oxidize one mole of ferrous oxalate
- The boiling point of 0.2 mol kg⁻¹ solution of X in water is greater than equimolal
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In which of the following conditions a chemical reaction can not occur
- In liquid-gas equilibrium,the pressure of vapours above the liquid is constant
- Which of the following does not show electrical conduction
- Number of moles of MnO₄⁻ required to oxidize one mole of ferrous oxalate
- The boiling point of 0.2 mol kg⁻¹ solution of X in water is greater than equimolal
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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