| ⇦ | 
| ⇨ |
What is the equivalent weight of SnCl₂ in the following reaction, SnCl₂+Cl₂→ SnCl₄?
Options
(a) 95
(b) 45
(c) 60
(d) 30
Correct Answer:
95
Explanation:
Equivalent weight of SnCl₂= mol. wt./2
= (119+ 2x 35.5)/2
= 193/2 = 95
Related Questions: - The intermediate formed in aldol condensation is
- The given reaction 2FeCl₃ + SnCl₂ → 2FeCl₂ + SnCl₄ is an example of
- Which of the following compounds will gives positive test with Tollen’s reagent
- Which one of the following is employed as a tranquilizer
- 40 mL of 0.1 M ammonia solution is mixed with 20 mL of 0.1 M HCl.
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The intermediate formed in aldol condensation is
- The given reaction 2FeCl₃ + SnCl₂ → 2FeCl₂ + SnCl₄ is an example of
- Which of the following compounds will gives positive test with Tollen’s reagent
- Which one of the following is employed as a tranquilizer
- 40 mL of 0.1 M ammonia solution is mixed with 20 mL of 0.1 M HCl.
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply