| ⇦ | 
| ⇨ |
Volume occupied by one molecule of water (density= 1 g cm⁻³) is
Options
(a) 9 x 10⁻²³ cm³
(b) 6.023 x 10⁻²³ cm³
(c) 3 x 10⁻²³ cm³
(d) 5.5 x 10⁻²³ cm³
Correct Answer:
3 x 10⁻²³ cm³
Explanation:
density = mass/volume
volume=mass/density
=1 gram/ 1 gram cm⁻³ = 1 cm³
1 g water= 1/18 moles of water
(at wt of H *2 + at wt of oxygen = 18)
volume occupied by 1 molecules of water = (18 / (6.02 x 10²³)) cm³
= 3 x 10⁻²³ cm³
Related Questions: - Unpleasent smelling carbylamines are formed by heating alkali and chloroform with
- Beryllium and aluminium exhibit many properties which are similar.
- Which of the following has a higher rate of reaction with water
- Which of the following reagents can be used to convert primary amides into pri
- The strongest reducing agent is
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Unpleasent smelling carbylamines are formed by heating alkali and chloroform with
- Beryllium and aluminium exhibit many properties which are similar.
- Which of the following has a higher rate of reaction with water
- Which of the following reagents can be used to convert primary amides into pri
- The strongest reducing agent is
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply