Volume occupied by one molecule of water (density= 1 g cm⁻³) is

Volume Occupied By One Molecule Of Water Density 1 G Chemistry Question

Volume occupied by one molecule of water (density= 1 g cm⁻³) is

Options

(a) 9 x 10⁻²³ cm³
(b) 6.023 x 10⁻²³ cm³
(c) 3 x 10⁻²³ cm³
(d) 5.5 x 10⁻²³ cm³

Correct Answer:

3 x 10⁻²³ cm³

Explanation:

density = mass/volume
volume=mass/density
=1 gram/ 1 gram cm⁻³ = 1 cm³
1 g water= 1/18 moles of water
(at wt of H *2 + at wt of oxygen = 18)
volume occupied by 1 molecules of water = (18 / (6.02 x 10²³)) cm³
= 3 x 10⁻²³ cm³

Related Questions:

  1. Activated charcoal is used to remove colouring matter from pure substances.
  2. Which one of the following compounds will react with NaHCO₃ solution to give
  3. Aufbau principle does not give the correct arrangement of filling up of atomic
  4. Hydro-metallurgical process of extraction of metals is based on
  5. Electronic configuration of hydride ion is

Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*