| ⇦ | 
| ⇨ |
Vapour pressure of dilute aqueous solution of glucose is 750 mm of mercury at 373K. The mole fraction of solute is
Options
(a) 1/76
(b) 1/7.6
(c) 1/38
(d) 1/0.1
Correct Answer:
1/76
Explanation:
p(s) = p⁰(1 – x₂).
⇒ 750 = 760(1 – x₂) or 750/760 = 1 – x₂, or 750/760 -1 = -x₂
⇒ x₂ = 1/76.
Related Questions: - The first fractional product of petroleum from top to bottom is
- Which of the following pairs of transition metal ions are the stronger oxidisi
- Chloride ion and potassium ion are isoelectronic. Then
- The pyknometric density of sodium chloride crystal is 2.165 x 10³ kg m⁻³,
- The number of oxygen atoms in 4.4g of CO₂ is
Topics: Solid State and Solutions
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The first fractional product of petroleum from top to bottom is
- Which of the following pairs of transition metal ions are the stronger oxidisi
- Chloride ion and potassium ion are isoelectronic. Then
- The pyknometric density of sodium chloride crystal is 2.165 x 10³ kg m⁻³,
- The number of oxygen atoms in 4.4g of CO₂ is
Topics: Solid State and Solutions (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply