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Unit of reduction factor is
Options
(a) ampere
(b) ohm
(c) tesla
(d) weber
Correct Answer:
ampere
Explanation:
Reduction factor K = i/tan θ
.·. i = K tanθ
The unit of current (i) is ampere. So, the unit of reduction factor (K) is equivalent to that of current (i).
Related Questions: - The focal length of the objective of a terrestrial telescope is 80 cm
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- The current in the coil of inductance 5H decreases at the rate of 2 A/s
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Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Physical World and Measurement
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The focal length of the objective of a terrestrial telescope is 80 cm
- The friction of the air causes a vertical retardation equal to 10%
- The current in the coil of inductance 5H decreases at the rate of 2 A/s
- In Young’s double slit experiment, the intensity of light coming from the first slit
- When 4 A current flows for 2 min in an electroplating experiment,
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Physical World and Measurement (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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Reduction factor of say Tangent Galvanometer is actually numerically equal to the current in ampere needed to produce a deflection of 45° when plane of coil lies in magnetic meridian
K=Itan(theta). I has unit ampere and (theta) is the ratio b/w opposite side and adjacent side so length by length. therefore tan (theta) has no unit. So unit of K is Ampere.