| ⇦ |
| ⇨ |
Two waves are represented by the equations y₁ = a sin (?t + kx + 0.57) m and y₂ = a cos (?t + kx) m, where x is in meter and t in sec. The phase difference between them is
Options
(a) 1.0 radian
(b) 1.25 radian
(c) 1.57 radian
(d) 0.57 radian
Correct Answer:
1.0 radian
Explanation:
Here, y₁ = a sin (?t + kx + 0.57 )
and y₂ = a cos (?t + kx )
= a sin [π/2 + (?t – kx)
Phase difference, ∆? = ?¬ツツ – ?¬ツチ
= π/2 – 0.57 = 3.14 / 2 – 0.57 = 1.57 – 0.57
1 radian
Related Questions: - An electron revolves in a circle at the rate of 10¹⁹ rounds per second.
- A simple pendulum has a time period T₁ when on the earth’s surface and T₂ When taken
- A car of mass m starts from rest and accelerates so that the instantaneous
- The momentum is most closely related to
- A thin and circular disc of mass M and radius R is rotating in a horizontal plane
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An electron revolves in a circle at the rate of 10¹⁹ rounds per second.
- A simple pendulum has a time period T₁ when on the earth’s surface and T₂ When taken
- A car of mass m starts from rest and accelerates so that the instantaneous
- The momentum is most closely related to
- A thin and circular disc of mass M and radius R is rotating in a horizontal plane
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply