| ⇦ | 
| ⇨ |
Two thin long conductors seprated by a distance d carry currents I₁ and I₂ in the same direction. They exert a force F on each other. Now, the current in one of them is increased to two times and its direction is reversed. The distance is also increased to 3d. The new value of force between them is
Options
(a) (-2F)
(b) F/3
(c) (-2F/3)
(d) (-F/3)
Correct Answer:
(-2F/3)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The focal lengths of a converging lens are fᵥ and fᵣ for violet and red lights
- Given the value of Rydberg constant is 10⁷ m⁻¹, the wave number of the last line
- If X=3YZ², find dimensions of Y if X and Z are the dimensions of capacity
- The velocity of a particle at an instant is 10 ms⁻¹.After 3 s its velocity will become
- Two radioactive materials X₁ and X₂ have decay constants 5λ and λ respectively
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The focal lengths of a converging lens are fᵥ and fᵣ for violet and red lights
- Given the value of Rydberg constant is 10⁷ m⁻¹, the wave number of the last line
- If X=3YZ², find dimensions of Y if X and Z are the dimensions of capacity
- The velocity of a particle at an instant is 10 ms⁻¹.After 3 s its velocity will become
- Two radioactive materials X₁ and X₂ have decay constants 5λ and λ respectively
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply