| ⇦ | 
| ⇨ |
Two springs with spring constants K₁=1500 N/m and K₂=3000 N/m are stretched by the same force. The ratio of potential energy stored in springs will be
Options
(a) 1:2
(b) 2:1
(c) 4:1
(d) 1:4
Correct Answer:
2:1
Explanation:
Force F=-Kxdisplacement (x),
Potential Energy = U =(1/2) Kx²
U = (1/2) K(F/K)² = (1/2)(F²/K)
U₁/U₂=(1/2)(F²/K₁)x(2K₂/F²)
K₂/K₁=3000/1500=2/1.
Related Questions: - The instantaneous values of alternating current and voltages in a circuit are given as
- Alternating current is transmitted to distant places at
- A car is moving in a circular horizontal track of radius 10.0 m with a constant speed
- A planet in a distinct solar system is 10 times more massive than the earth
- A paramagnetic sample shows a net magnetisation of 0.8 Am⁻¹, when placed
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The instantaneous values of alternating current and voltages in a circuit are given as
- Alternating current is transmitted to distant places at
- A car is moving in a circular horizontal track of radius 10.0 m with a constant speed
- A planet in a distinct solar system is 10 times more massive than the earth
- A paramagnetic sample shows a net magnetisation of 0.8 Am⁻¹, when placed
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply