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Two spherical nuclei have mass numbers 216 and 64 with their radii R₁ and R₂, respectively. The ratio, R₁/R₂ is equal to
Options
(a) (3:2)
(b) (1:3)
(c) (1:2)
(d) (2:3)
Correct Answer:
(3:2)
Explanation:
Radius of nuclei having mass number A is determined as
R = R₀ A¹/³ (where R₀ = constant)
where, R₀ = 1.2 x 10⁻¹⁵ m
This implies, R₁/R₂ = (A₁/A₂)¹/³ = (216/64)¹/³ = 6/4
R₁:R₂ = 3:2
Related Questions: - A Gaussian surface in the cylinder of cross-section πa² and length L is immersed
- When a biconvex lens of glass having refractive index 1.47 is dipped in a liquid
- During an adiabatic process, the cube of the pressure is found to be inversely
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A Gaussian surface in the cylinder of cross-section πa² and length L is immersed
- When a biconvex lens of glass having refractive index 1.47 is dipped in a liquid
- During an adiabatic process, the cube of the pressure is found to be inversely
- If the focal length of a concave mirror is 50 cm, then where should the object
- The ratio of the nuclear radii of elements with mass numbers 216 and 125 is
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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R=R°A^1/3. (R°=constant
R1÷R2 =(A1÷A2)^1/3
=(216÷64)^1/3
=6÷4.
=> R1:R2 = 3:2