| ⇦ | 
| ⇨ |
Two spherical nuclei have mass numbers 216 and 64 with their radii R₁ and R₂, respectively. The ratio, R₁/R₂ is equal to
Options
(a) (3:2)
(b) (1:3)
(c) (1:2)
(d) (2:3)
Correct Answer:
(3:2)
Explanation:
Radius of nuclei having mass number A is determined as
R = R₀ A¹/³ (where R₀ = constant)
where, R₀ = 1.2 x 10⁻¹⁵ m
This implies, R₁/R₂ = (A₁/A₂)¹/³ = (216/64)¹/³ = 6/4
R₁:R₂ = 3:2
Related Questions: - An explosion blows a rock into three parts. Two parts go off at right angles to each other
- A mass m moving horizontally (along the x-axis) with velocity v collides and sticks
- At place on earth, the vertical component of earth’s magnetic field is √3 times
- When the temperature increases, the viscocity of
- A body of mass m is orbiting the earth at a radius r from the center of earth
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An explosion blows a rock into three parts. Two parts go off at right angles to each other
- A mass m moving horizontally (along the x-axis) with velocity v collides and sticks
- At place on earth, the vertical component of earth’s magnetic field is √3 times
- When the temperature increases, the viscocity of
- A body of mass m is orbiting the earth at a radius r from the center of earth
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
R=R°A^1/3. (R°=constant
R1÷R2 =(A1÷A2)^1/3
=(216÷64)^1/3
=6÷4.
=> R1:R2 = 3:2