| ⇦ | 
| ⇨ |
Two spherical nuclei have mass numbers 216 and 64 with their radii R₁ and R₂, respectively. The ratio, R₁/R₂ is equal to
Options
(a) (3:2)
(b) (1:3)
(c) (1:2)
(d) (2:3)
Correct Answer:
(3:2)
Explanation:
Radius of nuclei having mass number A is determined as
R = R₀ A¹/³ (where R₀ = constant)
where, R₀ = 1.2 x 10⁻¹⁵ m
This implies, R₁/R₂ = (A₁/A₂)¹/³ = (216/64)¹/³ = 6/4
R₁:R₂ = 3:2
Related Questions: - The time period of a thin bar magnet in Earth’s magnetic field is T
- If the red light is replaced by blue light illuminating the object in a microscope
- A particle moves in xy plane according to the equation x = 4t² + 5t + 16 and y = 5t
- 24 cells of emf 1.5 V each having internal resistance of 1 ohm are connected
- Two identical long conducting wires AOB and COD are placed at right angle
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The time period of a thin bar magnet in Earth’s magnetic field is T
- If the red light is replaced by blue light illuminating the object in a microscope
- A particle moves in xy plane according to the equation x = 4t² + 5t + 16 and y = 5t
- 24 cells of emf 1.5 V each having internal resistance of 1 ohm are connected
- Two identical long conducting wires AOB and COD are placed at right angle
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
R=R°A^1/3. (R°=constant
R1÷R2 =(A1÷A2)^1/3
=(216÷64)^1/3
=6÷4.
=> R1:R2 = 3:2