| ⇦ | 
| ⇨ |
Two spheres A and B of masses m1 and m2 respectively collide. A is at rest initially and B is moving with velocity v along x-axis. After collision B has a velocity v/2 in a direction perpendicular to the original direction. The mass A moves after collision in the direction
Options
(a) same as that of B
(b) Opposite to that of B
(c) θ = tan⁻¹ (1/2) to the x-axis
(d) θ = tan⁻¹ ( -1/2) to the x-axis
Correct Answer:
θ = tan⁻¹ (1/2) to the x-axis
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Two bodies of masses m₁ and m₂ are initially at rest at infinite distance apart
- The shortest wavelength in Lyman series is 91.2 nm. The largest wavelength
- The most stable particle in Baryon group is
- A proton beam enters a magnetic field of 10⁻⁴ Wb/m² normally. If the specific charge
- A stone tied to the end of a string of 1 m long is whirled in a horizontal circle
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two bodies of masses m₁ and m₂ are initially at rest at infinite distance apart
- The shortest wavelength in Lyman series is 91.2 nm. The largest wavelength
- The most stable particle in Baryon group is
- A proton beam enters a magnetic field of 10⁻⁴ Wb/m² normally. If the specific charge
- A stone tied to the end of a string of 1 m long is whirled in a horizontal circle
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply