| ⇦ |
| ⇨ |
Two spheres A and B of masses m1 and m2 respectively collide. A is at rest initially and B is moving with velocity v along x-axis. After collision B has a velocity v/2 in a direction perpendicular to the original direction. The mass A moves after collision in the direction
Options
(a) same as that of B
(b) Opposite to that of B
(c) θ = tan⁻¹ (1/2) to the x-axis
(d) θ = tan⁻¹ ( -1/2) to the x-axis
Correct Answer:
θ = tan⁻¹ (1/2) to the x-axis
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The depth at which the effective value of acceleration due to gravity is g/4
- Imagine a new planet having the same density as that of earth but it is 3 times bigger
- A and B are two metals with threshold frequencies 1.8 x 10¹⁴ Hz and 2.2 x 10¹⁴ Hz.
- To what temperature should the hydrogen at room temperature (27°C) be heated at constant
- A body of mass 4 kg is accelerated upon by a constant force travels
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The depth at which the effective value of acceleration due to gravity is g/4
- Imagine a new planet having the same density as that of earth but it is 3 times bigger
- A and B are two metals with threshold frequencies 1.8 x 10¹⁴ Hz and 2.2 x 10¹⁴ Hz.
- To what temperature should the hydrogen at room temperature (27°C) be heated at constant
- A body of mass 4 kg is accelerated upon by a constant force travels
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply