| ⇦ | 
| ⇨ |
Two sources P and Q produce notes of frequency 660 Hz each. A listener moves from P to Q with a speed of 1 ms⁻¹. If the speed of sound is 330 m/s, then the number of beats heard by the listener per second will be
Options
(a) zero
(b) 4
(c) 8
(d) 2
Correct Answer:
4
Explanation:
∆f / f = v / C
(beats) /2 / f = v / C
Beats = 2 fv / C = 4
Related Questions: - A particle of mass 1.96×10⁻¹⁵ kg is kept in equilibrium between two horizontal metal
- The liquid-crystal phase of a matter is called
- A resistance R draws power P when connected to an AC source. If an inductance
- Two lines of force due to a bar magnet
- A small oil drop of mass 10⁻⁶kg is hanging in at rest between two plates seperated
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle of mass 1.96×10⁻¹⁵ kg is kept in equilibrium between two horizontal metal
- The liquid-crystal phase of a matter is called
- A resistance R draws power P when connected to an AC source. If an inductance
- Two lines of force due to a bar magnet
- A small oil drop of mass 10⁻⁶kg is hanging in at rest between two plates seperated
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply