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Two sources P and Q produce notes of frequency 660 Hz each. A listener moves from P to Q with a speed of 1 ms⁻¹. If the speed of sound is 330 m/s, then the number of beats heard by the listener per second will be
Options
(a) zero
(b) 4
(c) 8
(d) 2
Correct Answer:
4
Explanation:
∆f / f = v / C
(beats) /2 / f = v / C
Beats = 2 fv / C = 4
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle is under two mutually perpendicular simple harmonic motions
- An electron of mass m and a photon have same energy E. The ratio of de-Broglie
- The unit of electric permittivity is
- When one of the slits of Young’s experiment is covered with a transport sheet
- The maximum number of possible interference maxima for slit-seperation equal to
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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