| ⇦ |
| ⇨ |
Two resistors of 6Ω and 9Ω are connected in series to a 120 V source. The power consumed by 6Ω resistor is
Options
(a) 384Ω
(b) 616Ω
(c) 1500Ω
(d) 1800Ω
Correct Answer:
384Ω
Explanation:
Equivalent resistance in series = 6 + 9 = 15 Ω
Current flow in circuit, i = V / R = 120 / 15 = 8 A
Voltage in 6Ω resistor, V = iR = 8 × 6 = 48 V
Power consumed by 6Ω resistor,
P = V² / R = (48 × 48) / 6 = 8 × 48 = 384 W
Related Questions: - A galvanometer having resistance of 50 Ω requires a current of 100μA to give full
- A body travels 200 cm in the first two seconds and 220 cm in the next 4 secs
- Pick out the correct statements from the following
- In a mass spectrometer used for measuring the masses of ions, the ions
- The temperature coefficient of the resistance of a wire is 0.00125 per ⁰C.
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A galvanometer having resistance of 50 Ω requires a current of 100μA to give full
- A body travels 200 cm in the first two seconds and 220 cm in the next 4 secs
- Pick out the correct statements from the following
- In a mass spectrometer used for measuring the masses of ions, the ions
- The temperature coefficient of the resistance of a wire is 0.00125 per ⁰C.
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply