| ⇦ | 
| ⇨ |
Two resistors of 6Ω and 9Ω are connected in series to a 120 V source. The power consumed by 6Ω resistor is
Options
(a) 384Ω
(b) 616Ω
(c) 1500Ω
(d) 1800Ω
Correct Answer:
384Ω
Explanation:
Equivalent resistance in series = 6 + 9 = 15 Ω
Current flow in circuit, i = V / R = 120 / 15 = 8 A
Voltage in 6Ω resistor, V = iR = 8 × 6 = 48 V
Power consumed by 6Ω resistor,
P = V² / R = (48 × 48) / 6 = 8 × 48 = 384 W
Related Questions: - The rest energy of an electron is
- A particle is executing a simple harmonic motion. Its maximum acceleration
- A plane wave of wavelength 6250Å is incident normally on a slit of width 2×10⁻² cm.
- The initial rate of increase of current, when a battery of emf 6 V is connected
- The Bohr model of atoms
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The rest energy of an electron is
- A particle is executing a simple harmonic motion. Its maximum acceleration
- A plane wave of wavelength 6250Å is incident normally on a slit of width 2×10⁻² cm.
- The initial rate of increase of current, when a battery of emf 6 V is connected
- The Bohr model of atoms
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply