Two resistors of 6Ω and 9Ω are connected in series to a 120 V source.

Two Resistors Of 6 And 9 Are Connected In Series Physics Question

Two resistors of 6Ω and 9Ω are connected in series to a 120 V source. The power consumed by 6Ω resistor is

Options

(a) 384Ω
(b) 616Ω
(c) 1500Ω
(d) 1800Ω

Correct Answer:

384Ω

Explanation:

Equivalent resistance in series = 6 + 9 = 15 Ω

Current flow in circuit, i = V / R = 120 / 15 = 8 A

Voltage in 6Ω resistor, V = iR = 8 × 6 = 48 V

Power consumed by 6Ω resistor,

P = V² / R = (48 × 48) / 6 = 8 × 48 = 384 W

Related Questions:

  1. Stress to strain ratio is equivalent to
  2. The current in a self-inductance L=40 mH is to be increased uniformly from 1A to 11 A
  3. If ∆Q>0 when heat flows into a system, ∆W>0 when work is done on the system
  4. A thin prism of angle 15⁰ made of glass of refractive index µ₁ = 1.5 is combined
  5. The horizontal range and maximum height attained by a projectile are R and H,respectively

Topics: Current Electricity (136)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*