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Two planets at mean distances d₁ and d₂ from the sun have their frequencies n₁ and n₂ respectively. Then
Options
(a) n₁²d₁²=n₂²d₂²
(b) n₁²d₁³=n₂²d₂³
(c) n₁d₁²=n₂d₂²
(d) n₁²d₁=n₂²d₂
Correct Answer:
n₁²d₁³=n₂²d₂³
Explanation:
Apply Kepler’s third law, T²∞R³
T²/R³=constant
Given: T=1/n and R=d
T²/R³=1/n².1/d³=constant
n²d³=constant
For the two planets,n₁²d₁³=n₂²d₂³
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A astronomical telescope has objective and eye-piece of focal lengths
- A body initially at rest is moving with uniform acceleration a m/s²
- A rocket with a lift-off mass 3.5 x 10⁴ kg is blasted upwards with an initial acceleration
- A rod of weight W is supported by two parallel knife edge A and B
- A car of mass 1000 kg negotiates a banked curve of radius 90 m on a frictionless
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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