| ⇦ | 
| ⇨ |
Two planets at mean distances d₁ and d₂ from the sun have their frequencies n₁ and n₂ respectively. Then
Options
(a) n₁²d₁²=n₂²d₂²
(b) n₁²d₁³=n₂²d₂³
(c) n₁d₁²=n₂d₂²
(d) n₁²d₁=n₂²d₂
Correct Answer:
n₁²d₁³=n₂²d₂³
Explanation:
Apply Kepler’s third law, T²∞R³
T²/R³=constant
Given: T=1/n and R=d
T²/R³=1/n².1/d³=constant
n²d³=constant
For the two planets,n₁²d₁³=n₂²d₂³
Related Questions: - A light emitting diode(LED) has a voltage drop of 2 volt across it
- A lift is moving down with acceleration a.A man in the lift drops a ball
- The string of a pendulum is horizontal.The mass of bob attached to it is m
- If ∆Q>0 when heat flows into a system, ∆W>0 when work is done on the system
- In a transistor, the value of βis 100, then the value of α will be
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A light emitting diode(LED) has a voltage drop of 2 volt across it
- A lift is moving down with acceleration a.A man in the lift drops a ball
- The string of a pendulum is horizontal.The mass of bob attached to it is m
- If ∆Q>0 when heat flows into a system, ∆W>0 when work is done on the system
- In a transistor, the value of βis 100, then the value of α will be
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply