| ⇦ |
| ⇨ |
Two pendulums A and B are oscillating simultaneously with time period T and 5T/4 respectively. What is the phase difference between them after B completes one oscillation?
Options
(a) 60°
(b) 45°
(c) 90°
(d) 30°
Correct Answer:
90°
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - When a p-n junction is reverse biased, then the current through the junction
- Two bodies of mass 10 kg and 5 kg moving in concentric orbits of radius
- 1 curie is equal to
- The maximum number of possible interference maxima for slit-seperation equal to
- If ₉₂U²³⁸ undergoes successively 8 ∝-decays and 6 β-decays, the resulting nucleus is
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When a p-n junction is reverse biased, then the current through the junction
- Two bodies of mass 10 kg and 5 kg moving in concentric orbits of radius
- 1 curie is equal to
- The maximum number of possible interference maxima for slit-seperation equal to
- If ₉₂U²³⁸ undergoes successively 8 ∝-decays and 6 β-decays, the resulting nucleus is
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply