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Two nuclei have their mass numbers into the ratio of 1:3. The ratio of their nucleus densities would be
Options
(a) 1 : 3
(b) 3 : 1
(c) (3)¹/³ : 1
(d) 1 : 1
Correct Answer:
1 : 1
Explanation:
Required ratio of nuclear densities = ρ₁ / ρ₂
(M₁ / V₁) / (M₂ / V₂) = M₁ / M₂ x V₂ / V₁ = 1/3 x 4/3 πR₂³ / 4/3 πR₁³
1/3 x (R₂ / R₁)³ = 1/3 x (R₀M₂¹/³ / R₀M₁¹/³)³ [ R = R₀M¹/³ ]
= 1/3 x (M₂ / M₁) = 1/3 x (3/1) = 1 : 1
Related Questions: - A body is thrown upward from ground covers equal distances
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body is thrown upward from ground covers equal distances
- By the succesive disintegration of ₉₂U²³⁸, the final product obtained is ₈₂Pb²⁰⁶, then
- Two spherical conductors A and B of radii 1 mm and 2 mm are separated by a distance
- ₉₂U²³⁵ undergoes successive disintegrations with the end product of ₈₂P²⁰³
- The temperature coefficient of a resistance wire is 0.00125 per degree.
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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