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Two metallic spheres of radii 1 cm and 3 cm are given charges of -1 x 10⁻² C and 5 x 10⁻² C, respectively. If these are connected by a conducting wire, the final charge on the bigger sphere is:
Options
(a) 2 x 10⁻² C
(b) 3 x 10⁻² C
(c) 4 x 10⁻² C
(d) 1 x 10⁻² C
Correct Answer:
3 x 10⁻² C
Explanation:
At equilibrium potential of both sphere becomes same if charge of sphere one x where Q= 4 x 10 10⁻² C
v₁ = v₂ kx / 1cm = k(Q – x) / 3 cm
3x = Q – x 4x = Q
x = Q/4 = 4 x 10⁻² / 4 C = 1 x 10⁻²
Q’ = Q – x = 3 x 10⁻² C
Related Questions: - In p- type semiconductor, the acceptor level lies
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Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In p- type semiconductor, the acceptor level lies
- Two thin dielectric slabs of dielectric constants K₁ and K₂, (K₁ < K₂) are inserted
- In Moseley’s law √ν=a(z-b), the values of the screening constant for K-series
- The 6563 Å line emitted by hydrogen atom in a star is found to be red shifted by 5Å
- If the value of potential in an A.C circuit is 10 V, the peak value of potential is
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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