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Two metallic spheres of radii 1 cm and 3 cm are given charges of -1 x 10⁻² C and 5 x 10⁻² C, respectively. If these are connected by a conducting wire, the final charge on the bigger sphere is:
Options
(a) 2 x 10⁻² C
(b) 3 x 10⁻² C
(c) 4 x 10⁻² C
(d) 1 x 10⁻² C
Correct Answer:
3 x 10⁻² C
Explanation:
At equilibrium potential of both sphere becomes same if charge of sphere one x where Q= 4 x 10 10⁻² C
v₁ = v₂ kx / 1cm = k(Q – x) / 3 cm
3x = Q – x 4x = Q
x = Q/4 = 4 x 10⁻² / 4 C = 1 x 10⁻²
Q’ = Q – x = 3 x 10⁻² C
Related Questions: - Surface tension of a solution is 30 x 10⁻² N/m. The radius of the soap bubble is 5 cm
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Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Surface tension of a solution is 30 x 10⁻² N/m. The radius of the soap bubble is 5 cm
- The limiting angle of incidence for an optical ray that can be transmitted
- Fission of nuclei is possible because the binding energy per nucleon in them
- Photons of 5.5 eV energy fall on the surface of the metal emitting photoelectrons
- A conducting sphere of radius R is given a charge Q. The electric potential
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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