⇦ | ⇨ |
Two metallic spheres of radii 1 cm and 3 cm are given charges of -1 x 10⁻² C and 5 x 10⁻² C, respectively. If these are connected by a conducting wire, the final charge on the bigger sphere is:
Options
(a) 2 x 10⁻² C
(b) 3 x 10⁻² C
(c) 4 x 10⁻² C
(d) 1 x 10⁻² C
Correct Answer:
3 x 10⁻² C
Explanation:
At equilibrium potential of both sphere becomes same if charge of sphere one x where Q= 4 x 10 10⁻² C
v₁ = v₂ kx / 1cm = k(Q – x) / 3 cm
3x = Q – x 4x = Q
x = Q/4 = 4 x 10⁻² / 4 C = 1 x 10⁻²
Q’ = Q – x = 3 x 10⁻² C
Related Questions: - The moderator in a reactor
- When indensity of radiation is increased on a photosensitive plate, then
- A certain current on passing through a galvanometer produces a deflection
- A charged particle enters a uniform magnetic field with a certain speed at right angles
- A circuit contains an ammeter, a battery of 30 V and a resistance 40.8 ohm
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The moderator in a reactor
- When indensity of radiation is increased on a photosensitive plate, then
- A certain current on passing through a galvanometer produces a deflection
- A charged particle enters a uniform magnetic field with a certain speed at right angles
- A circuit contains an ammeter, a battery of 30 V and a resistance 40.8 ohm
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply