| ⇦ | 
| ⇨ |
Two metal rods 1 and 2 of same lengths have same temperature difference between their ends. Their thermal conductivities are K₁ and K₂ and cross sectional areas A₁ and A₂, respectively. If the rate of heat conduction in rod 1 is four times that in rod 2, then
Options
(a) K₁A₁ = K₂A₂
(b) K₁A₁ = 4K₂A₂
(c) K₁A₁ = 2K₂A₂
(d) 4K₁A₁ = K₂A₂
Correct Answer:
K₁A₁ = 4K₂A₂
Explanation:
Q = 4Q (Given)
K₁A₁ ∆t / L= 4 K₂A₂ ∆t / L
K₁A₁ = 4K₂A₂
Related Questions:
- The rate of increase of thermo-e.m.f. with temperature at the neutral temperature
- If alpha, beta and gamma rays carry same momentum, which has the longest
- A body is hangfing from a rigid support by an inextensible string of length
- Two spheres of mass m and M are situated in air and the gravitational force
- A sample of radioactive element has a mass of 10 gram at an instant t=0.
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply