| ⇦ | 
| ⇨ |
Two identical charges repel each other with a force equal to 10 mgwt they are 0.6 m apart in air. (g=10 ms⁻²). The value of each charge is
Options
(a) 2 mC
(b) 2×10⁻⁷ mC
(c) 2 nC
(d) 2 μC
Correct Answer:
2 μC
Explanation:
F = (1 / 4πε₀) (q₁q₂ / d²)
Therefore, (10 × 10⁻³) × 10 = [(9 × 10⁹) × q²] / (0.06)²
or, q² = (10⁻¹ × 0.36) / (9 × 10⁹) = 4 / 10¹² = 4 × 10⁻¹²
or, q = 2 × 10⁻⁶ C = 2 μC
Related Questions: - To convert a 800 mV range millivoltmeter of resistance 40Ω into an ammeter of 100 mA
- The charge flowing through a resistance R varies with time t as Q=at-bt²,
- If longitudinal strain for a wire is 0.03 and its poisson’s ratio is 0.5
- A uniform rod of length l is placed with one end in contact with the horizontal
- A wire of one metre length carries a constant current. The wire is bent to form
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- To convert a 800 mV range millivoltmeter of resistance 40Ω into an ammeter of 100 mA
- The charge flowing through a resistance R varies with time t as Q=at-bt²,
- If longitudinal strain for a wire is 0.03 and its poisson’s ratio is 0.5
- A uniform rod of length l is placed with one end in contact with the horizontal
- A wire of one metre length carries a constant current. The wire is bent to form
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
F =kq^2/r^2
10^-1 = 9×10^9×q^2/.6^2
√10^-10×.36/9=q
10^-5×.2=q or q2uc {u=10^-6}