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Two bodies of masses m₁ and m₂ are initially at rest at infinite distance apart.They are then allowed to move towards each other under mutual gravitational attraction with the escape velocity .Their relative velocity of approach at a separation distance r between them is
Options
(a) [2 G(m₁- m₂ )/r]¹/²
(b) [2 G(m₁+m₂ )/r]¹/²
(c) [r/2G(m₁m₂)]¹/²
(d) [2G / r(m₁m₂)]¹/²
Correct Answer:
[2 G(m₁+m₂ )/r]¹/²
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When volume of a system is increased two times and temperature is decreased
- An object of mass 3kg is at rest. Now a force F=6t² i⃗+4t j⃗ is applied on the object
- A transformer rated at 10 kW is used to connect a 5 kV transmission line to a 240 V
- A nucleus ᴢXᴬ emits an α- particle with velocity v. The recoil speed of the daughter
- In cyclotron, for a given magnet, radius of the semicircle traced by positive ion
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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