| ⇦ | 
| ⇨ |
Two bodies of masses m₁ and m₂ are initially at rest at infinite distance apart.They are then allowed to move towards each other under mutual gravitational attraction with the escape velocity .Their relative velocity of approach at a separation distance r between them is
Options
(a) [2 G(m₁- m₂ )/r]¹/²
(b) [2 G(m₁+m₂ )/r]¹/²
(c) [r/2G(m₁m₂)]¹/²
(d) [2G / r(m₁m₂)]¹/²
Correct Answer:
[2 G(m₁+m₂ )/r]¹/²
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions:
- Angular momentum of the particle rotating with a central force is constant due to
- You are marooned on a frictionless horizontal plane and cannot exert any horizontal
- The r.m.s speed of the molecules of a gas in a vessel is 400 m/s
- The upper half of an inclined plane of inclination θ is perfectly smooth while lower
- What is the value of incidence L for which the current is maximum in a series LCR
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply