⇦ | ⇨ |
Time period of the rotation of the earth about its own axis is 24 hour. Mass and radius of the earth are 6 x 10²⁴ kg and 6.4 x 10⁶ m respectively. The rotational kinetic energy of the earth about its own axis is
Options
(a) 2.6 x 10²⁹ J
(b) 2.6 x 10²⁴ J
(c) 2.6 x 10³² J
(d) 2.6 x 10³⁴ J
Correct Answer:
2.6 x 10²⁹ J
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - If energy(E), velocity(V) and time(T) are chosen as fundamental quantities,
- A circular disc of radius R is removed from a bigger circular disc of radius 2R
- The barrier potential of a p-n junction depends on
- The moment of inertia of a thin circular disc about an axis passing through its centre
- The effective length of magnet is 31.4 cm and its pole strength is 0.8Am.
Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If energy(E), velocity(V) and time(T) are chosen as fundamental quantities,
- A circular disc of radius R is removed from a bigger circular disc of radius 2R
- The barrier potential of a p-n junction depends on
- The moment of inertia of a thin circular disc about an axis passing through its centre
- The effective length of magnet is 31.4 cm and its pole strength is 0.8Am.
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply