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Three particles A,B and C are thrown from the top of a tower with the same speed. A is thrown straight up, B is thrown straight down and C is thrown horizontally. They hit the ground with speed V(A),V(B) and V(C) respectively.
Options
(a) V(A)=V(B)=V(C)
(b) V(B)>V(C)>V(A)
(c) V(A)=V(B)>V(C)
(d) V(A)>V(B)=V(C)
Correct Answer:
V(A)=V(B)>V(C)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A certain mass of Hydrogen is changed to Helium by the process of fusion
- When an α-particle of mass m moving with velocity ν bombards on a heavy nucleus
- A spherical drop of mercury having a potential of 2.5 v is obtained as a result
- A transistor-oscillator using a resonant circuit with an inductor L
- If the pressure of gas is increased from 1.01×10⁵ Pa to 1.165×10⁵ Pa and volume
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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