⇦ | ⇨ |
Three particles A,B and C are thrown from the top of a tower with the same speed. A is thrown straight up, B is thrown straight down and C is thrown horizontally. They hit the ground with speed V(A),V(B) and V(C) respectively.
Options
(a) V(A)=V(B)=V(C)
(b) V(B)>V(C)>V(A)
(c) V(A)=V(B)>V(C)
(d) V(A)>V(B)=V(C)
Correct Answer:
V(A)=V(B)>V(C)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The horizontal range of a projectile is 4√3 times the maximum height achieved
- The ratio of specific heats Cp/Cv=γ in terms of degrees of freedom (n) is given by
- The magnetic moment of a diamagnetic atom is
- If capillary experiment is performed in vaccum, then a liquid under the condition
- The threshold frequency for a metallic surface corresponds to an energy of 6.2 eV,
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The horizontal range of a projectile is 4√3 times the maximum height achieved
- The ratio of specific heats Cp/Cv=γ in terms of degrees of freedom (n) is given by
- The magnetic moment of a diamagnetic atom is
- If capillary experiment is performed in vaccum, then a liquid under the condition
- The threshold frequency for a metallic surface corresponds to an energy of 6.2 eV,
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply