⇦ | ![]() | ⇨ |
Three capacitors of capacitances 3 μF, 10 μF and 15 μF are connected in series to a voltage source of 100V. The charge on 15 μF is
Options
(a) 500 μC
(b) 100 μC
(c) 200 μC
(d) 280 μC
Correct Answer:
200 μC
Explanation:
Equivalent capacitance = C
1/C = 1/3 + 1/10 + 1/15 = (10 + 3 + 2) / 30 = 15 / 30 = 1 / 2
⇒ C = 2 μF
Charge through each capacitor is same as they are joined in series.
Q = CV = 2 × 100 = 200 μC
Related Questions:
- An alternating voltage e=200s in100t is applied to a series combination
- A particle has initial velocity (3i + 4j) and acceleration (0.1 i+0.3j). It’s speed after 10s
- The electirc field in a certain region is acting radially outward and is given by E=Ar.
- Two blocks of masses m₁=4 kg and m₂= 2kg are connected to the ends of a string
- In a region, the potential is represented by V(x,y,z)=6x-8xy-8y+6yz, where V
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply