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The work done in which of the following processes is equal to the change in internal energy of the system?
Options
(a) Adiabatic process
(b) Isothermal process
(c) Isochoric process
(d) None of these
Correct Answer:
Adiabatic process
Explanation:
In adiabatic process, dQ = 0
dQ = dU + dW ⇒ dU + dW = 0 ⇒ dU = -dW
In Adiabatic process, work done = change in dU.
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Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two thin lenses of focal lengths f₁ and f₂ are in contact and coaxial.
- Young’s modulus of the material of a wire is 18×10¹¹ dyne cm⁻².its value in SI is
- The maximum velocity of a particle, executing simple harmonic motion with an amplitude
- A charged particle (charge q) is moving in a circle of radius R with uniform speed v
- Four identical cells of emf Ԑ and internal resistance r are to be connected in series.
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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